X^2 + y^2 - 12x + 4y + 40 = 0

Question

X^2 + y^2 - 12x + 4y + 40 = 0

Answer 1

X²+y²-12x+4y+40=0
(x²-12x+36)+(y²+4y+4)-36-4+40=0
(x-6)²+(y+2)²=0
x-6=0  и  y+2=0
x=6         y=-2