№1 а) Sinx = -1
x = -π/2 + 2πk , k ∈Z
б) Cosx = √2/2
x = +-π/4 + 2πk , k ∈Z
в) tgx = -√3
x =-π/3 + πk , k ∈Z
№2 а)Сos²x - Cosx -2 = 0
по т. Виета: Cosx = 2, Cosx = -1
∅ x = π + 2πk , k ∈Z
б) 3Cos²x - 2Sinx +2 = 0
3(1- Sin²x) -2Sinx +2 = 0
3 - 3Sin²x - 2Sinx +2 = 0
3Sin² x +2Sinx -5 = 0
D = b² - 4ac = 4 -4*3*(-5) = 64
Sinx =-9/6 Sinx = 7/6
∅ ∅