Помогите решить пожалуйста
(3/14)*log₇d²=(3*2/14)*log₇d=(3/7)*(-7)=-3. log₄6*log√₆16=(1/log₆4)*log₆√16=log₆4/log₆4=1. 14^((1/3)*log₆8-log₆(1/3)=14^(log₆∛8+log₆3)= =14^(log₆2+log₆3)=14^log₆(2*3)=14^log₆6=14^1=14.