Cos 2x -7cos^2 x +4=0 Решите уравнение
2cos²x - 1 - 7cos²x + 4 = 0 5cos²x = 3 cos²x = 3/5 cosx = + - √(3/5) x = + - arccos√(3/5) x = + - (π - arccos√(3/5))