Program pr_1; var x,y,sum, umn: integer; begin write ('x='); readln (x); write ('y=');...

Question

Program pr_1;
var
x,y,sum, umn: integer;
begin
write ('x=');
readln (x);
write ('y=');
readln (y);
sum:=x+y;
umn:=x*y;
writeln ('sum=',sum);
writeln ('umn=',umn);
readln;
end.
x=25 y=36
sum=?
umn=?

Answer 1

При x=25, y=36;

sum=25+36=61umn=25*36=900

Comments

благодарю

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можешь решить 8mod3=

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и 18div8

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8mod3=2

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спасибо а 18div8

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18div8=2