Срочно вычислить определенный интеграл!

Решите задачу:

$\int\limits^e_1 (x^{-1}+1)dx=ln|x|+x|^e_1=ln|e|+e-ln|1|-1=1+e-1=e$

$\int\limits^0_{-1} \frac{(3x-1)^4}{7}dx = \frac{1}{21}\int\limits^0_{-1}(3x-1)^4d(3x-1)=\frac{1}{21}(\frac{(3x-1)^5}{5}|^0_{-1})=\\=\frac{1}{21}(-\frac{1}{5}+\frac{1024}{5})=\frac{1023}{21*5}=\frac{341}{35}=9\frac{26}{35}$

$\int\limits^\frac{\pi}{12}_\frac{\pi}{6} (\frac{2}{cos^22x}-cos2x) dx =- \int\limits^\frac{\pi}{6}_\frac{\pi}{12} (\frac{2}{cos^22x}-cos2x) dx=\\=-(tg2x-\frac{1}{2}sin2x|^\frac{\pi}{6}_\frac{\pi}{12})=-(\sqrt3-\frac{\sqrt3}{4}-\frac{\sqrt3}{3}+\frac{1}{4})=-(\frac{5\sqrt3+3}{12})$