Найти массовый долю Ca CO3

Question

Найти массовый долю Ca CO3

Answer 1

Mr(CaCO3)=40+12+16*3=100

ω(Сa  )=( 40 /100)*100% =40%
ω(С  )=(  12/100)*100%  =12%
ω(O )=( 48 /100)*100%  =48%

Answer 2

Mr(CaCO3) = 40 + 12 + 16*3 = 100
W(Ca) = Ar(Ca) * n / Mr(CaCO3)  *100% = 40 *1 / 100  *100% = 40%
W(C) = Ar(C) * n / Mr(CaCO3)  *100% = 12*1 / 100 *100% = 12%
W(O) = Ar(O) * n / Mr(CaCO3) *100% = 16*3 / 100 *100% = 48%