Помогите решить 2 примера. Они обведены синим.

1)
$8 \frac{22}{27} + (21 \frac{5}{14} * \frac{1}{6} ): (10 \frac{13}{42} - 9 \frac{13}{28} + 2 \frac{5}{24} ) - ( \frac{8}{9} * \frac{1}{9} ) : 2= \\ \\ =8 \frac{22}{27} + (\frac{21*14+5}{14} * \frac{1}{6} ): (10 \frac{52}{168} - 9 \frac{78}{168} + 2 \frac{35}{168} ) - \frac{8}{81} * \frac{1}{2} = \\ \\ =8 \frac{22}{27} + \frac{299*1}{14*6} : ( (10 - 9 + 2) + \frac{52 + 35 - 78}{168} ) - \frac{4*1}{81*1} = \\ \\$
$=8 \frac{22}{27} + \frac{299}{84} : 3 \frac{9}{168} - \frac{4}{81} = \\ \\ = 8 \frac{22}{27} + \frac{299}{84} * \frac{168}{513} - \frac{4}{81} = \\ \\ =8 \frac{66}{81} + \frac{299*2}{1*513} - \frac{4}{81} = 8 \frac{62}{81} - 1 \frac{85}{513} = \\ \\ = 8 \frac{3534}{4617} - 1 \frac{765}{4617} = 7 \frac{2769}{4617} =7 \frac{923}{1539}$

2.
$\frac{(2,4 - \frac{3}{4} )*0,6}{ \frac{3}{8}+0,25*0,4 } + \frac{7}{6-5 \frac{13}{20} } +1,04= \\ \\ = \frac{(2,40 - 0,75)*0,6}{0,375 +0,1} + \frac{7}{6,00-5,65} +1,04= \\ \\ = \frac{1,65*0,6}{0,475} + \frac{7}{0,35} + 1,04 = \\ \\ = \frac{0,99}{0,475} + \frac{1}{0,05} +1,04= \\ \\ = \frac{99}{100} * \frac{1000}{475} + 20 +1,04= \\ \\ = \frac{99*2}{1*95} +21,04 = 2 \frac{8}{95} +21 \frac{1}{25} = \\ \\ =2 \frac{40}{475} +21 \frac{19}{475} = 23 \frac{59}{475}$