Решите уравнение sinx-cosx=1
Sinx - cosx = 1 делим на √2 1/√2sinx - 1/√2cosx = 1/√2 sinx·cos(π/4) - cosx·sin(π/4) = 1/√2 sin(x - π/4) = 1/√2 x - π/4 = π/4 + 2πn или x - π/4 = 3π/4 + 2πk x = π/2 + 2πn x = π + 2πk