Помогите решииить))))

Решите задачу:

$\frac{\sqrt{3}-\sqrt{2}}{\sqrt[4]{3}+\sqrt[4]{2}}=\\ \frac{(\sqrt[4]{3}-\sqrt[4]{2})(\sqrt{3}-\sqrt{2}))}{\sqrt{3}-\sqrt{2}}=\\ \frac{(\sqrt[4]{3}-\sqrt[4]{2})*(3-2)}{(3-2)}=\sqrt[4]{3} - \sqrt[4]{2}\\ \\$

$\frac{19}{\sqrt[3]{100}-\sqrt[3]{90}+\sqrt[3]{81}}-\sqrt[3]{10}-\sqrt[3]{9}=\\ \frac{19-\sqrt[3]{10}(\sqrt[3]{100}-\sqrt[3]{90}+\sqrt[3]{81})-\sqrt[3]{9}(\sqrt[3]{100}-\sqrt[3]{90}+\sqrt[3]{81})}{\sqrt[3]{100}-\sqrt[3]{90}+\sqrt[3]{81}}=\\$
$\frac{19-10+\sqrt[3]{900}-\sqrt[3]{810}-\sqrt[3]{900}+\sqrt[3]{810}-9}{\sqrt[3]{100}-\sqrt[3]{90}+\sqrt[3]{81}}=0\\$