ребята помогите, не могу решить уравнение.....надо решить 77, 78.

(\frac{5}{3};+oo)\\ y+1=(2\sqrt{3y-5}-2)^2\\ y+1=4(3y-5)-8\sqrt{3y-5}+4\\ y+1=12y-16-8\sqrt{3y-5} \\ -11y+17 =8\sqrt{3y-5} \\ (17-11y)^2=64(3y-5)\\ 289-374y+121y^2=192y-320 \\ 121y^2-566y+609=0\\ y=3\\ " alt="\sqrt{y+1}=2\sqrt{3y-5}-2\\ ODZ=>(\frac{5}{3};+oo)\\ y+1=(2\sqrt{3y-5}-2)^2\\ y+1=4(3y-5)-8\sqrt{3y-5}+4\\ y+1=12y-16-8\sqrt{3y-5} \\ -11y+17 =8\sqrt{3y-5} \\ (17-11y)^2=64(3y-5)\\ 289-374y+121y^2=192y-320 \\ 121y^2-566y+609=0\\ y=3\\ " align="absmiddle" class="latex-formula">

$\sqrt{1-y}*\sqrt{y}=y\\ y-y^2=y^2\\ y=2y^2\\ 2y=1\\ y=0.5$