Srednee arifmeticheskoe dvux chisel 12.01, a odno iz nix ravno 18.43. Naydite drugoe chislo
X=18.43 y=? (x+y)/2=12.01 (18.43+y)=24.02 y=24.02-18.43=5.59 проверка (5.59+18.43)/2= 24.02.2=12.01 Ответ 5.59
(18,43+х):2= 12,01 18,43+х= 12,01*2 18,43+х=24,02 Х= 24,02-18,43 х= 5,59 ----------- (18,43+5,59):2=12,01 24,02:2= 12,01 12,01= 12,01
sps bolwoeee:)