( 3x - 2y² )² - ( 2y² + 3x )( 3x - 2y² ) + 2 =
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3x = a ; 2y² = b
( a - b )² - ( b + a )( a - b ) + 2 = ( a - b )² - ( a² - b² ) + 2 = a² - 2ab + b² - a² + b² + 2 = 2b² - 2ab + 2 = 2( b² - ab + 1 )
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2( 4y⁴ - 3x*2y² + 1 ) = 2( 4y⁴ - 6xy² + 1 ) = 8y⁴ - 12xy² + 2
ОТВЕТ 8y⁴ - 12xy² + 2