A)(c^2)^4*c^5\c^12 б)(x-3)(x-7)-(x-2)(x+2) в)(3а+4)^2-24a

Question

A)(c^2)^4*c^5\c^12
б)(x-3)(x-7)-(x-2)(x+2)
в)(3а+4)^2-24a

Answer 1

А). (с^ 2*4) * (c ^ 5-12) = c^8 * c ^-7 = c ^ 8+(-7) = c

б). x^2 - 7x - 3x + 21 - x^2 +4 = -7x-3x+21 +4 = -10x +25
-10x=-25
x=-25/-10
x= 2,5

 в). 9a^2 + 24a + 16 -24a = 9a^2 + 16
9a^2 = -16
a^2 = -16/9
a = -4/3