Решить систему {ху -2(х+у)=2 { ху+х+у=29
X+y=29-xy xy-2*(29-xy)=2 xy-58+2xy=2 3xy=60 xy=30 x+y+30=29 x+y=-1 x=-1-y -(1+y)*y-2(-1-y+y)=2 -(y+y^2)-2(-1)=2 -(y+y^2)+2=2 -y^2-y=0 y(-y-1)=0 -y(y+1)=0 y1=0 y2=-1 x1=-1-0=-1 x2=-1-(-1)=-1+1=0