(√(11-∛(x+7)))²=3²
11-∛(x+7)=9
-∛(x+7)=-2 |×(-1)
∛(x+7)=2
(∛(x+7))³=2³
x+7=8
x=1.
3)
(∛(24+√(x²+5)))³=3³
24+√(x²+5)=27
√(x²+5)=3
(√(x²+5))²=3²
x²+5=9
x²=4
x₁=2 x₂=-2
5)
(√(1+∛(x²+4x+6)))²=2²
1+∛(x²+4x+6)=4
∛(x²+4x+6)=3
(∛(x²+4x+6))³=3³
x²+4x+6=27
x²+4x-21=0 D=100
x₁=-7 x₂=3.