A
f`(x)=-2sinx-√2=0
sinx=√2/2⇒x=π/4∈[-π;π] U x=3π/4∈[-π;π]
f(-π)=2cos(-π)-√2*(-π)=-2+√2*π≈2,4 наиб
f(π/4)=2cosπ/4-√2*π/4=√2-√2π/4=3√2π/4≈-0,3
f(3π/4)=2cos3π/4-√2*3π/4=-√2-3√2π/4≈-4,7 наим
f(π)=2cosπ-√2π-2-√2π≈-2,4
б
f`(x)=√3+2sinx=0
sinx=-√3/2⇒x=-π/3∈[-π;π] U x=-2π/3∈[-π;π]
f(-π)=-√3π-2cos(-π)=-√3π+2≈-3,4
f(-2π/3)=-2√3π/3-2cos(-2π/3)=-2√3π/3-2*1/2≈-4,9 наим
f(-π/3)=-√3π/3-2cos(-π/3)=-√3π/3-2*1/2≈-2,8
f(π)=√3π-2cosπ=√3π-2*(-1)≈10,7 наиб
в
f`(x)=√3-2sinx=0
sinx=√3/2⇒x=π/3∈[0;π] U x=2π/3∈[0;π]
f(0)=√3*0+2cos0=0+2=2 наим
f(π/3)=√3π/3+2cosπ/3=√3π/3+2*1/2≈2,8
f(2π/3)=2√3π/3+2cos2π/3=2√3π/3+2*1/2=4,6 наиб
f(π)=√3π+2cosπ=√3π+2*(-1)≈3,3