Дано
m(C2H5OH)=23 kg=23000 g
m(пракCH3COH)=17.6 kg = 17600 g
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η-?
23000 X
C2H5OH-->CH3COH+H2 M(C2H5OH)=46 g/mol M(CH3COH)=44 g/mol
46 44
X=23000*44 / 46
X=22000 g
η = m(теор) /m(прак)*100% = 22000/23000 * 100%=95.7 %
ответ 95.7%