Найдите область определения функциии

$y= \sqrt{7x-2x^2} + \frac{2x+3}{9-4 x^{2} }$

$\left \{ {{7x-2x^2 \geq 0} \atop {9-4x^2 \neq 0}} \right.$

$\left \{ {{2x^2-7x \leq 0} \atop {(3-2x)(3+2x) \neq 0}} \right.$

$\left \{ {{x(2x-7) \leq 0} \atop {3-2x \neq 0}} \atop {3+2x \neq 0}} \right.$

$\left \{ {{x(2x-7) \leq 0} \atop {2x \neq 3}} \atop {2x \neq -3}} \right.$

$\left \{ {{x(2x-7) \leq 0} \atop {x \neq 1.5}} \atop {x \neq -1.5}} \right.$

$x(2x-7)=0$

$2x-7=0$ или $x=0$

$2x=7$

$x=3.5$

   + - +
----------------[0]--------------[3.5]----------------
////////////////
-----(-1.5)------------(1.5)-------------------------

$D(y)=[0;1.5)$ ∪ $(1.5;3.5]$