(bn) :q=2 n=7 S7=635 знайти b1 b7
Сумма S = b1 * (1-q^n) / (1-q) S7 = b1 * (1-2^7) / (1-2) = 635 b1 * 127 = 635 b1 = 5 Шестой член b6 = b1 * q^5 = 5 * 2^5 = 160