Log6(x+1)+log 6(2x+1)<=1

$log_6(x+1)+log _6(2x+1) \leq 1$
$log_6((x+1)(2x+1)) \leq 1$
$(x+1)(2x+1) \leq 6$
$2x^2+3x+1-6 \leq 0$
$2x^2+3x-5 \leq 0$
$(x-1)(x+2,5) \leq 0$
ОДЗ: $\left \{ {{x+1 \ \textgreater \ 0} \atop {2x+1 \ \textgreater \ 0}} \right. =\ \textgreater \ \left \{ {{x \ \textgreater \ -1} \atop {x \ \textgreater \ -0,5}} \right. =\ \textgreater \ x \ \textgreater \ -0,5$
x∈[1;∞)