Y=1-x² y=x²-x-2 S=?
1-x²=x²-x-2
2x²-x-3=0 D=25
x=1,5 x=-1
S=₋₁∫¹`⁵(1-x²-(x²-x-2)dx=₋₁∫¹`⁵(1-x²-x²+x+2)dx=₋₁∫¹`⁵(-2x²+x+3)dx=
=(-2x³/3+x²/2+3x) |¹`⁵₋₁=-2*(1,5)³/3+(1,5)²+3*1,5-(-2*(-1)³/3+(-1)²/2+3*(-1))=
=-2,25+1,125+4,5-(2/3+1/2-3)=-1,125+4,5-(7/6-3)=3,375+1⁵/₆=
=3³/₈+11/6=27/8+11/6=(81+44)/24=125/24.
Ответ: S=125/24≈5,2 кв. ед.