Решите уравнение: Sin2x-4sin^2x=0
2SinxCosx -4Sin²x = 0 | : Сos²x ≠ 0 2tgx - 4tg²x = 0 tgx(2 - 4tgx) = 0 tgx = 0 или 2 - 4tgx = 0 x = πn , n∈Z tgx = 1/2 x = arctg1/2 + kπ, k ∈Z