Решите уравнение: Sin2x-4sin^2x=0 Спасибо.
Sin 2x - 4sin^2 x = 0 2sin x*cos x - 4sin^2 x = 0 2sin x*(cos x - 2sin x) = 0 1) sin x = 0; x1 = pi*k 2) cos x = 2sin x sin x/cos x = tg x = 1/2 x2 = arctg(1/2) + pi*n