(z-3)×(z+2)=36Пж помогите

Question

(z-3)×(z+2)=36
Пж помогите

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Answer 1

(z - 3) * (z + 2) = 36,
z² + 2z - 3z - 6 = 36,
z² - z - 6 = 36,
z² - z - 6 - 36 = 0,
z² - z - 42 = 0,
Д = (-1)² - 4 * 1 * (-42) = 1 + 168 = 169,
z1 = (1 + 13) / 2*1 = 14 / 2 = 7,
z2 = (1 - 13) / 2*1 = -12 / 2 = -6 

Answer 2

Z^2+2z-3z-6=36;z^2-z-42=0; D=(-1)^2-4*1*(-42)=169; z1=(1-13)/2, z2=(1+13)/2. z1= -6, z2=7. Ответ: z1= -6, z2=7.