5.
x≤3-1/(x-1) ОДЗ: х-1≠0 х≠1
x-3+1/(x-1)≤0
(x*(x-1)-3*(x-1)+1)/(x-1)≤0
(x²-x-3x+3+1)/(x-1)≤0
(x²-4x+4)/(x-1)≤0
(x-2)²/(x-1)≤0
{x-2=0 x=2
{x-1<0 x<1 ⇒<br>Ответ: х∈(-∞;1)U[2].
6.
√(2+5x-3x²)+ln(x-1)=√(x²+x-6)
ОДЗ:
{2+5x-3x²≥0 |×(-1) 3x²-5x-2≤0 (x-2)(x+1/3)≤0 x∈[-1/3;2]
{x²+x-6≥0 (x+3)(x-2)≥0 x∈(-∞;-3]U[2;+∞)
{x-1>0 x>1 ⇒
-∞ //////////////////////////////-3______-1/3ooo-1ooooooo[2]///////////////////////+∞
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Ответ: x=2.