Помогите срочно!!!!!!!!!!!

Решите задачу:

$6sin^2x-sinx-1 \leq 0\\\\D=1+24=25\; ,\; \; (sinx)_1=- \frac{1}{3}\; ,\; \; (sinx)_2= \frac{1}{2}\\\\+++[-\frac{1}{3}\, ]---[\, \frac{1}{2} \, ]+++\\\\-\frac{1}{3} \leq sinx \leq \frac{1}{2}\\\\x\in [-arcsin\frac{1}{3}+2\pi n\, ;\, \frac{\pi}{6}+2\pi n\, ]\cup [\, \frac{5\pi}{6}+2\pi n\, ;\, \pi +arcsin \frac{1}{3}+2\pi n\, ],\\\\n\in Z$