∛(m³-6m²n+12mn²-8n³)/(2n-m)=∛(m³-3*m²*2n+3*m*(2n)²-(2n)²)/(2n-m)=
=∛(m-2n)³/(2n-m)=(m-2n)/(2n-m)=-(m-2n)/(m-2n)=-1.
log₄64-log₄(1/16)-3*log₄2=log₄2⁶-log₄2⁻⁴-log₄2³=log₄(2⁶/(2⁻⁴*2³)=
=log₄(2⁶/2⁻¹)=log₄2⁷=7*log₄2=7*log₂²2=(7/2)*log₂2=3,5.
(1/4)ˣ+(1/4)ˣ⁻¹>5
(1/4)ˣ+(1/4)ˣ/(1/4)>5
(1/4)ˣ+4/(1/x)>5
5*(1/4)ˣ>5 |÷5
(1/4)ˣ>1
(1/4)ˣ>(1/4)⁰
Так как (1/4)<0 ⇒<br>x<0</strong>.