1
(x-2)/(x+3)-30/[(x-30(x+3)=1/6
ОЗ 6(x-3)(x+3)≠0⇒x≠3,x≠-3
(x-3)(x-2)-30=x²-9
x²-3x-2x+6-30-x²=-9
-5x=-9+24
-5x=15
x=15:(-5)
x=-3 не удов усл
х∈∅
2
(x-2)/9x+1)+5/(x-1)=6/[(x-1)(x+1)]
ОЗ (x-1)(x+1)≠0⇒x≠1,x≠-1
(x-1)(x-2)+5(x+1)=6
x²-2x-x+2+5x+5-6=0
x²+2x+1=0
(x+1)²=0
x+1=0
x=-1 не удов усл
х∈∅
3
(x-9)/(x+1)+(x-3)/(x-1)=8/[(x-1)(x+1)]
ОЗ (x-1)(x+1)≠0⇒x≠1,x≠-1
(x-1)(x-9)+(x+1)(x+3)=8
x²-x-9x+9+x²+x+3x+3-8=0
2x²-6x+4=0
x²-3x+2=0
x1+x2=3 U x1*x2=2
x1=2 U x2=1- не удов усл
4
(x+1)/(x-2)+9/[(x-2)(x-5)=(x-2)/(x-5)
ОЗ (x-1)(x-5)≠0⇒x≠1,x≠5
(x-5)(x+1)+9=(x-2)²
x²+x-5x-5+9-x²+4x-4=0
0=0
x∈R