Найдите tg a если sin a=-5/13 и пи<a<3пи/2

Question

Найдите tg a если sin a=-5/13 и пи<a<3пи/2

Answer 1

Сosa=-√(1-sin²a)=-√(1-25/169)=-√(144/169)=-12/13
tga=sina/cosa=-5/13:(-12/13)=5/13*13/12=5/12

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