Help! 1) 4^x+1 +15*2^x-1 -1=0 2)log4^2 x-log4 x-2=0

Решите задачу:

$4^{x+1}+15*2^{x-1}-1=0\\4*4^x+15*2^x*2^{-1}-1=0\\2^x=a,a\ \textgreater \ 0\\8a^2+15a-2=0\\D=15^2-4*8*(-2)=225+64=289=17^2\\a_1=\frac{-15+17}{16}=\frac{1}{8}\\a_2=\frac{-15-17}{16}=-2\\2^x=\frac{1}{8}\to x=-3\\\\\boxed{OTBET:C}$

$log_4^2x-log_4x-2=0\to\left[\begin{array}{ccc}log_4x_1=-1\\log_4x_2=2\end{array}\right\to\left[\begin{array}{ccc}x_1=\frac{1}{4}\\x_2=16\end{array}\right\\\\\boxed{OTBET:A}$