3*(2х + y - 1) = 5x + 4y +2
4*(x - 2y + 1) = 2x -5y +16
6x + 3y - 3 = 5x + 4y +2
4x - 8y + 4 = 2x -5y +16
6x - 5x + 3y - 4y = 2 + 3
4x - 2x - 8y + 5y = 16 - 4
x - y = 5
2x - 3y = 12
x = 5 +y
2*(5+y) - 3y = 12
10 + 2y - 3y = 12
-y = 12 - 10
-y = 2
y = -2
x = 5 - 2 = 3
Ответ: x = 3
y = -2