Log0.2(3x-5)>=log0.2(x+2)

$log_{0.2}(3x-5) \geq log_{0.2}(x+2)$
ОДЗ:
$\left \{ {3x-5\ \textgreater \ 0} \atop {x+2\ \textgreater \ 0}} \right.$
$\left \{ {3x\ \textgreater \ 5} \atop {x\ \textgreater \ -2}} \right.$
$\left \{ {x\ \textgreater \ 1 \frac{2}{3} } \atop {x\ \textgreater \ -2}} \right.$
$x$ ∈ $(1 \frac{2}{3} ;+$ ∞ $)$

$3x-5 \leq x+2$
$3x-x \leq 2+5$
$2x \leq 7$
$x \leq 3.5$

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Ответ: $(1 \frac{2}{3};3.5]$