Очень срочно (x^3+4x^2+2x-1):(x+1)
(x³+4x²+2x-1)/(x+1)=(x³+2x²+x+2x²+x-1)/(x+1)=(x*(x²+2x+1)+(2x²+x-1))/(x+1)= =(x*(x+1)²+2*(x+1)*(x-0,5))/(x+1)=(x+1)*(x*(x+1)+2x-1)/(x+1)=x²+3x-1.