{z+3>3z-1⇒3z-z<3+1⇒2z<4⇒z<2<br>{5z-1>6-2z⇒5z+2z>6+1⇒7z>7⇒z>1
{z-3<0⇒z<3<br>\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
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x∈(1;2)
{0,7(1+5z)<0,5(z+1)+3z⇒0,7+3,5z<0,5z+0,5+3z⇒3,5z-3,5z<-0,7 нет решен<br>{2z-(2-1,7)>6,7⇒2z-0,3>6,7⇒2z>7⇒z>3,5
x∈∅