1)y=f(a)+f'(a)(x-a)
f(4)=2*4^2-4*√4-2=32-8-2=22
f'(x)=4x+2/√x
f'(4)=4*4+2/√4=16+1=17
y=22+17(x-4)
y=17x-46
2) y`(x)=12-3(x+2)^2
y'=0
12-3(x+2)^2=0
4-(x+2)^2=0
(2-x-2)(2+x+2)=0
-x(x+4)=0
x=0 x=-4
y(-4,5)=12*(-4,5)-(-4,5+2)^3=-54+274,625=220,625
y(-4)=12*(-4)-(-4+2)^3=-48+8=-40
y(0)=8
y(0,5)=12*0,5-(0,5+2)^3=6-15,625=-9,625
yнаим=-40
yнаиб=220,625