Помогите решить эти задания

Question 1

Question 2

Решите задачу:

$14*\sqrt[4]{27}*\sqrt[12]{27}=14*\sqrt[4]{27}*\sqrt[4]{3}=14*\sqrt[4]{27*3}=14*3=42$

$25*\sqrt[5]{16}*\sqrt[20]{16}=25*\sqrt[5]{16}*\sqrt[5]{2}=25*\sqrt[5]{16*2}=25*2=50$

$0,65*\sqrt[5]{625}*\sqrt[20]{625}=0,65*\sqrt[5]{625}*\sqrt[5]{5}=0,65*\sqrt[5]{625*5}=\\=0,65*5=3,25$

$\frac{\sqrt[6]{72}*\sqrt[3]{9}}{\sqrt[6]{8}}=\sqrt[6]{9}*\sqrt[3]{9}=\sqrt[3]{3}*\sqrt[3]{9}=\sqrt[3]{3*9}=3$

$\frac{\sqrt[9]{27}}{\sqrt[9]{216}*\sqrt[3]{4}}=\frac{1}{\sqrt[9]{8}*\sqrt[3]{4}}=\frac{1}{\sqrt[3]{2}*\sqrt[3]{4}}=\frac{1}{\sqrt[3]{8}}=\frac{1}{2}=0,5$

Question 3

Решите задачу:

$14* \sqrt[4]{27} * \sqrt[4]{ \sqrt[3]{27} } = 14*\sqrt[4]{27}* \sqrt[4]{3} = 14* \sqrt[4]{27*3} = 14* \sqrt[4]{81} =14*3$ $=42$
$25* \sqrt[5]{16}* \sqrt[5]{ \sqrt[4]{16} } =25* \sqrt[5]{16}* \sqrt[5]{2} =25* \sqrt[5]{16*2} =25* \sqrt[5]{32}$ $=25*2=50$
$0,65* \sqrt[5]{625} * \sqrt[5]{ \sqrt[4]{625} } =0,65* \sqrt[5]{625} * \sqrt[5]{5} =0,65* \sqrt[5]{5^4*5}$ $= 0,65*5 = 3,25$
$\frac{ \sqrt[6]{9*8}* \sqrt[3]{9} }{ \sqrt[6]{8} } = \frac{ \sqrt[6]{9}* \sqrt[6]{8} * \sqrt[3]{9} }{ \sqrt[6]{8} } = \sqrt[6]{9} * \sqrt[3]{9}$ $= \sqrt[3]{ \sqrt{9} } * \sqrt[3]{9} = \sqrt[3]{3} * \sqrt[3]{9} = \sqrt[3]{9*3} = \sqrt[3]{27} = 3$
$\frac{ \sqrt[9]{27} }{ \sqrt[9]{216} * \sqrt[3]{4} } = \frac{ \sqrt[9]{27} }{ \sqrt[9]{27*8} * \sqrt[3]{4} } = \frac{ \sqrt[9]{27} }{ \sqrt[9]{27} * \sqrt[9]{8} * \sqrt[3]{4} }$ $= \frac{1}{ \sqrt[9]{8}* \sqrt[3]{4} } = \frac{1}{ \sqrt[3]{ \sqrt[3]{8} }* \sqrt[3]{4} } = \frac{1}{ \sqrt[3]{2}* \sqrt[3]{4} }$ $= \frac{1}{ \sqrt[3]{2*4} } = \frac{1}{ \sqrt[3]{8} } = \frac{1}{2} = 0,5$