Решите уравнение: 9х²-6х+1=0
9х^2-6х+1=0 D=b^2-4ac=6^2-4*9*1=36-36=0
9x^2 - 6x + 1 = 0 (3x - 1)^2 = 0 3x - 1 = 0 3x = 1 x = 1/3
9х²-6х+1=0 D=b²-4ac=6²-4*9=36-36=0 х1=(-b-√D)/2а=(6-0)/2*9=6/18=1/3 х2=(-b+√D)/2a=(6+0)/2*9=6/18=1/3 Ответ:1/3