Вычислите: 4 3/7:(6 2/15-8,2)+(49,75-27 1/12)*3

Решите задачу:

$\frac{4*7+3}{7} :( \frac{6*15+2}{15}- \frac{82}{10} )+( \frac{4975}{100} -\frac{27*12+1}{12} )*3= \frac{31}{7} :( \frac{92}{15}- \frac{41}{5} )+3*(\frac{199}{4}- \frac{325}{12} )=\frac{31}{7} :( \frac{92-41*3}{15} )+3*( \frac{199*3-325}{12} )=\frac{31}{7} :( \frac{-31}{15} )+3*( \frac{272}{12} )$
$=-\frac{31}{7}*\frac{15}{31}+68=- \frac{15}{7} +68=-2 \frac{1}{7} +68$