1) cos(3x/4)=0 2) sinx>-1/2 3) ctgx< или = 1

Question

1) cos(3x/4)=0
2) sinx>-1/2
3) ctgx< или = 1

Answer 1

1) cos(3x/4)=0
(3x/4)=π/2+πn, n∈Z
x=(4/3)(π/2+πn)=2π/3+4πn/3,  n∈Z

2) sinx>-1/2

2πn+π+arcsin(1/2) 2πn+π+π/6

3) ctgx≤ 1


(π/4  +πn)  ≤x <(π+πn),n∈Z<span>