2sin^2-3sinx*cos^2x =0Помагите

2sin²x-3sinx*cos²x=0
2sin²x-3sinx*(1-sin²x)=0
2sin²x-3sinx+3sin³x=0
sinx*(3sin²x+2sinx-3)=0
D=b²-4ac=4+36=50>0
(sinx)₁₂= $\frac{-2+- \sqrt{50} }{6} = \frac{-2+-5 \sqrt{2} }{6}$
Т.к. -1≤sinx≤1=> sinx= $\frac{-2+5 \sqrt{2} }{6}$
$\left \{ {{sinx=0} \atop {sinx= \frac{-2+5 \sqrt{2} }{6} }} \right.$
$\left \{ {{x= \pi k} \atop {x=(-1)^{n}arcsin( \frac{-2-5 \sqrt{2} }{6} )+ \pi n }} \right.$
n,k⊆Z