Sin2x+√3cos2x=cosπ/6cos2x+sinπ/6sin2x
sin2x+√3cos2x-√3/2cos2x-1/2sin2x=0/82
2sin2x+2√3cos2x-√3cos2x-sin2x=0
sin2x+√3cos2x=0/cos2x
tg2x+√3=0
tg2x=-√3
2x=-π/3+πk
x=-π/6+πk/2,k∈z
0<-π/6+πk/2<4π/3 /*(6/π)<br>0<-1+3k<8<br>1<3k<9<br>1/3k=1⇒x=-π/6+π/2=π/3
k=2⇒x=-π/6+π=5π/6