СРОЧНО !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Решите задачу:

$1)\; \; y= \frac{x^5+x^3+x}{x+1}\\\\ y'= \frac{(5x^4+3x^2+1)(x+1)-(x^5+x^3+x)\cdot 1}{(x+1)^2} =\\\\=\frac{5x^5+5x^4+3x^3+3x^2+x+1-x^5-x^3-x}{(x+1)^2} = \frac{4x^5+5x^4+2x^3+3x^2+1}{(x+1)^2}\\\\y'(1)=\frac{15}{4}=3,75$

$2)\; \; y= \frac{x^2-4}{\sqrt{x}} \; ;\; \; y=x^{\frac{3}{2}}- 4x^{-\frac{1}{2}} \\\\y'= \frac{3}{2}\cdot x^{\frac{1}{2}} -4\cdot (-\frac{1}{2})\cdot x^{-\frac{3}{2}}= \frac{3}{2}\cdot \sqrt{x}+\frac{2}{\sqrt{x^3} }\\\\y'(1)=\frac{3}{2}+2=3,5$