Дано
V(ppaNaOH)=320mL = 0.32 л
W(NaOH)=25%
p(NaOH)=1.3 g/mL
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m(NaOH)-?
Cм-?
m(NaOH)= V(ppaNaOH)*W(NaOH)*p(NaOH) / 100% = 320*25%*1.3 / 100% = 104 g
M(NaOH)=40 g/mol
n(NaOH)=104/40 = 2.6 mol
Cм = n(NaOH) / V(ppa) = 2.6 / 0.32 = 8.15 моль / л
ответ 104 г , 8.15 моль/л