РЕШИТЕ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Решите задачу:

$5\cdot 4^{x^2+4x}+20\cdot 10^{x^2+4x-1}-7\cdot 25^{x^2+4x}=0\\\\a)\; \; 5\cdot 2^{2(x^2+4x)}+2\cdot (5\cdot 2)^{x^2+4x}-7\cdot 5^{2(x^2+4x)}=0\; |:5^{2(x^2+4x)}\ \textgreater \ 0\\\\5\cdot \Big ( \frac{2}{5}\Big )^{2(x^2+4x)}+2\cdot \Big (\frac{2}{5} \Big )^{x^2+4x}-7=0\\\\t=\Big (\frac{2}{5}\Big )^{x^2+4x}\ \textgreater \ 0 \; ,\; \; 5t^2+2t-7=0\\\\D/4=1+35=36\; ,\; \; t_1= \frac{-1-6}{5}=- \frac{7}{5}=-1 \frac{2}{5}\ \textless \ 0\; \; ne\; podxodit\; (t\ \textgreater \ 0)\\\\t_2= \frac{-1+6}{5} =1\ \textgreater \ 0$

$\Big ( \frac{2}{5}\Big )^{x^2+4x}=1\; \; \Rightarrow \; \; x^2+4x=0$

$x(x+4)=0\\\\x_1=0\; ,\; \; x_2=-4\\\\b)\; \; x\in [-3,1\, ]\; :\; \; \; x=0\in [-3,1\, ]\\\\Otvet;\; \; a)\; \; x_1=0\; ,\; \; x_2=-4\; ;\; \; b)\; \; x=0\; .$