Масова частка сполуки H2SO3; Fe2(SO4)3

Question

Масова частка сполуки H2SO3; Fe2(SO4)3

Answer 1

Mr(H2SO3)=2*1+32+3*16=82
W(H)=2/82=0.02=2%
W(S)=32/82=0.39=39%
W(O)=48/82=0.59=59%

Mr(Fe2(SO4)3)=2*56+3*32+12*16=400
W(Fe)=112/400=0.28=28%
W(S)=96/400=0.24=24%
W(O)=192/400=0.48=48%