1й вариант, решите Срочно

Question

1й вариант, решите Срочно

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Answer 1

1) (e^x-sin(x))'=e^x-cos(x)
2) (sin(x-3)-ln(1-2x))'=cos(x-3)+2/(1-2x)
3) (3sin(x/4)-(1/2)*cos(x)+2e^x-3)'=(3/4)*cos(x/4)+(1/2)sin(x)+2e^x