X^2-8x+18=0 x1=? x2=?

Question

X^2-8x+18=0
x1=?
x2=?

Answer 1

X^2-8x+18=0
k=b/2 = (-8)/2 = -4
D1= k^2 -ac = 16-18 = -2
D1>-2
Корней не имеет.