Дано
m(KOH)=50 g
m(CO2)=50 g
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m(K2CO3)-?
M(KOH)=56 g/mol
n(KOH)=m/M= 50/56 = 0.89 mol
M(CO2)=44 g/mol
n(CO2)= m/M=50/44 = 1.14 mol
n(KOH) 50 X
2KOH+CO2-->K2CO3+H2O M(K2CO3)=138 g/mol
2*56 138
X=50*138 / 112 = 61.6 g
ответ 61.6 г