Помогите решить номер 8 и 9
((x^2-9)-(xy-3y))*(x(x+3)) / ((y(x+3)((x-y-3)(x-y+3))= =( (x-3)(x+3) -y(x-3))*x(x+3)) /( (y(x+3)(x-y+3)(x+3-y) )=((x-3)(x+3-y)x(x+3)) / /((y(x+3)(x-y+3)(x-y-3))=x(x-3) / y(x-y-3); x=-4; y=-2; (-4(-4-3) ) /(-2(-4+2-3)=28/10=2,8
Можете 9 сделать